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A243823
Quantity of "semitotatives," numbers m < n that are products of at least one prime divisor p of n and one prime q coprime to n.
22
0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 0, 1, 0, 3, 3, 4, 0, 3, 0, 5, 5, 6, 0, 6, 3, 8, 6, 9, 0, 5, 0, 11, 8, 11, 7, 11, 0, 13, 10, 14, 0, 12, 0, 16, 14, 17, 0, 18, 5, 19, 14, 20, 0, 21, 11, 22, 16, 23, 0, 19, 0, 25, 20, 26, 13, 25, 0, 27, 20, 27, 0, 31, 0, 30, 27, 31, 13, 32, 0, 35, 23, 34, 0, 33, 17, 36, 25, 38, 0, 35, 15, 39, 27, 40, 19, 45, 0, 44, 32, 46
OFFSET
1,14
COMMENTS
Semitotatives m < n have a regular factor that is the product of prime divisors of n, and a coprime factor that is the product of primes q that are coprime to n.
The unit fractions of semitotatives have a mixed recurrent expansion in base n (See Hardy & Wright).
REFERENCES
G. H. Hardy and E. M. Wright, An Introduction to the Theory of Numbers, Sixth Edition, Oxford University Press, 2008, pages 144-145 (last part of Theorem 136).
LINKS
M. De Vlieger, Exploring Number Bases as Tools, ACM Inroads, March 2012, Vol. 3, No. 1, pp. 4-12.
FORMULA
a(n) = A045763(n) - A243822(n).
a(n) = n + 1 - phi(n) - Sum_{1 <= k <= n, gcd(n, k) = 1} mu(k)*floor(n/k). - Michael De Vlieger, May 10 2016, after Benoit Cloitre at A010846.
EXAMPLE
For n = 10 with prime divisors {2, 5} and prime totatives {3, 7}, the only semitotative is 6. For n = 16, with the prime divisor 2 and the prime totatives {3, 5, 7, 11, 13}, there are four semitotatives {6, 10, 12, 14}.
MAPLE
f:= n -> n + 1 - numtheory:-phi(n) - add(numtheory:-mobius(k)*floor(n/k), k=select(t -> igcd(n, t)=1, [$1..n])):
map(f, [$1..100]); # Robert Israel, May 10 2016
MATHEMATICA
Table[n + 1 - EulerPhi@ n - Total[MoebiusMu[#] Floor[n/#] &@ Select[Range@ n, CoprimeQ[#, n] &]], {n, 120}] (* Michael De Vlieger, May 10 2016 *)
CROSSREFS
Sequence in context: A374362 A371274 A117032 * A281141 A078911 A353417
KEYWORD
nonn
AUTHOR
Michael De Vlieger, Jun 11 2014
STATUS
approved