OFFSET
0,2
FORMULA
a(2*k) = 10^(2*k-1) + 2*(10^k-1)/9; a(2*k+1) = 10^(2*k+1).
Conjecture: a(n) = 111*a(n-2)-1110*a(n-4)+1000*a(n-6) for n>6. - Colin Barker, Oct 07 2014
Empirical g.f.: -2*x*(50*x^5+50*x^4-155*x^3-55*x^2+6*x+5) / ((x-1)*(x+1)*(10*x-1)*(10*x+1)*(10*x^2-1)). - Colin Barker, Oct 07 2014
PROG
(Haskell)
import Data.List (elemIndex); import Data.Maybe (fromJust)
a248336 = fromJust . (`elemIndex` map a248327 [0..])
(PARI)
s=[0, 10]; for(k=1, 12, s=concat(s, [10^(2*k-1)+2*(10^k-1)/9, 10^(2*k+1)])); s \\ Colin Barker, Oct 07 2014
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Reinhard Zumkeller, Oct 05 2014
EXTENSIONS
Formula corrected by, and more terms from Colin Barker, Oct 07 2014
STATUS
approved