[go: up one dir, main page]

login

Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).

Sum of previous terms divided by their distance from n
0

%I #2 Mar 31 2012 10:25:22

%S 1,3,6,11,20,33,54,87,142,226,360,571,907,1438,2278,3606,5708,9032,

%T 14293,22614,35778,56604,89550,141670,224122,354560,560907,887348,

%U 1403768,2220731,3513149,5557726,8792197,13909055,22003808

%N Sum of previous terms divided by their distance from n

%F a(n) = n + floor(a(n-1)/1) + floor(a(n-2)/2) + ... + floor(a(1)/(n-1))

%e a(1)=1 by definition

%e a(4)=4+a(3)/1+a(2)/2+a(1)/3=4+floor(6/1)+floor(3/2)+floor(1/3)=11

%K nonn

%O 2,2

%A _Dominick Cancilla_, Aug 09 2010