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a(n) = [n*r +k*r]-[n*r]-[k*r], where r=1/sqrt(2), k=4, [ ]=floor.
3

%I #11 Sep 08 2022 08:45:56

%S 1,1,0,1,1,1,1,1,1,0,1,1,1,1,1,1,0,1,1,0,1,1,1,1,1,1,0,1,1,1,1,1,1,0,

%T 1,1,0,1,1,1,1,1,1,0,1,1,1,1,1,1,0,1,1,1,1,1,1,0,1,1,0,1,1,1,1,1,1,0,

%U 1,1,1,1,1,1,0,1,1,0,1,1,1,1,1,1,0,1,1,1,1,1,1,0,1,1,1,1,1,1,0,1,1,0,1,1,1,1,1,1,0,1,1,1,1,1,1,0,1,1,0,1,1,1,1,1,1,0,1,1,1,1,1,1,0,1,1

%N a(n) = [n*r +k*r]-[n*r]-[k*r], where r=1/sqrt(2), k=4, [ ]=floor.

%C See A187950.

%H G. C. Greubel, <a href="/A188395/b188395.txt">Table of n, a(n) for n = 1..10000</a>

%F a(n) = [n*r+4*r]-[n*r]-[4*r], where r=1/sqrt(2).

%t r=2^(-1/2); k=4;

%t t=Table[Floor[n*r+k*r]-Floor[n*r]-Floor[k*r], {n,1,220}] (* A188395 *)

%t Flatten[Position[t,0] ] (* A188396 *)

%t Flatten[Position[t,1] ] (* A188397 *)

%o (PARI) for(n=1,100, print1(floor((n+4)/sqrt(2)) - floor(n/sqrt(2)) - floor(4/sqrt(2)), ", ")) \\ _G. C. Greubel_, Apr 25 2018

%o (Magma) [Floor((n+4)/Sqrt(2)) - Floor(n/Sqrt(2)) - Floor(4/Sqrt(2)): n in [1..100]]; // _G. C. Greubel_, Apr 25 2018

%Y Cf. A187950.

%K nonn

%O 1

%A _Clark Kimberling_, Mar 30 2011