[go: up one dir, main page]

login
A126224
Determinant of the n X n matrix in which the entries are 1 through n^2, spiraling inward starting with 1 in the (1,1)-entry.
6
1, -5, -48, 660, 11760, -257040, -6652800, 198918720, 6745939200, -255826771200, -10727081164800, 492775291008000, 24610605962342400, -1327677426915840000, -76940526008586240000, 4766815315895592960000, 314406967644177408000000, -21995911456386651463680000
OFFSET
1,2
LINKS
Sergey Sadov, Problem 11270, American Mathematical Monthly, Vol. 114, No. 1, 2007, p. 78.
FORMULA
a(n) = (-1)^[n*(n-1)/2]*2^(2*n-3)*(3*n-1)*Product_{k=0..n-2} (1/2+k) for n>=2.
E.g.f.: (((-16*x^2-1)*sqrt(2*sqrt(16*x^2+1)+2)-8*sqrt(16*x^2+1)*x^2+16*x^2 + sqrt(16*x^2+1)+1)*sqrt(2*sqrt(16*x^2+1)-2)+(8*(sqrt(16*x^2+1)*x^2+2*x^2-(1/8) * sqrt(16*x^2+1)+1/8))*sqrt(2*sqrt(16*x^2+1)+2))/(512*x^3+32*x). - Robert Israel, Apr 20 2017
EXAMPLE
For n = 2, the 2 X 2 (spiral) matrix A is
[1, 2]
[4, 3]
Then a(2) = -5 because det(A) = 1*3 - 2*4 = -5.
MAPLE
a:=n->(-1)^(n*(n-1)/2)*2^(2*n-3)*(3*n-1)*product(1/2+k, k=0..n-2): seq(a(n), n=1..20);
# second Maple program:
a:= proc(n) option remember; `if`(n<2, (3*n+1)/4,
4*(1-3*n)*(2*n-5)*(2*n-3) *a(n-2) /(3*n-7))
end:
seq(a(n), n=1..20); # Alois P. Heinz, Jan 21 2014
MATHEMATICA
a[n_] := (-1)^(n*(n-1)/2)*2^(2n-3)*(3n-1)*Pochhammer[1/2, n-1]; Table[a[n], {n, 1, 20}] (* Jean-François Alcover, May 26 2015 *)
CROSSREFS
Cf. A023999 (absolute values). - Alois P. Heinz, Jan 21 2014
Sequence in context: A048435 A293102 A023999 * A360235 A108207 A127091
KEYWORD
sign
AUTHOR
Emeric Deutsch, Dec 31 2006
STATUS
approved