[go: up one dir, main page]

login

Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).

A111252
Primes p such that the difference between the closest squares surrounding p is prime.
1
2, 3, 5, 7, 11, 13, 29, 31, 37, 41, 43, 47, 67, 71, 73, 79, 83, 89, 97, 127, 131, 137, 139, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 331, 337, 347, 349, 353, 359, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 541, 547, 557, 563
OFFSET
1,1
COMMENTS
Conjecture: The number of terms in this sequence is infinite.
That there are infinitely many terms in this sequence would follow from the Legendre conjecture (one of the Landau problems - see the Weisstein link) that there is always a prime between n^2 and (n+1)^2. This is still an open problem. - Max Alekseyev, Apr 20 2006
LINKS
Eric Weisstein's World of Mathematics, Landau's Problems
FORMULA
Let p be a prime number and r = floor(sqrt(p)). Then the closest surrounding squares of p are r^2 and (r+1)^2. So d = (r+1)^2 - r^2 = 2r+1. If d is prime then list p.
EXAMPLE
29 is a prime number. 5^2 and 6^2 are the closest squares surrounding 29. Now the difference 36-25 = 11 is prime so 29 is in the table.
MATHEMATICA
Clear[f, lst, p, n]; f[n_]:=IntegerPart[Sqrt[n]]; lst={}; Do[p=Prime[n]; If[PrimeQ[a=(f[p]+1)^2-f[p]^2], AppendTo[lst, p]], {n, 6!}]; lst (* Vladimir Joseph Stephan Orlovsky, Aug 05 2009 *)
Select[Prime[Range@103], PrimeQ[2*Floor[Sqrt[#]]+1]&] (* Ivan N. Ianakiev, Jul 30 2015 *)
PROG
(PARI) surrsqpr(n) = { local(x, y, j, r, d); forprime(x=2, n, r=floor(sqrt(x)); d=r+r+1; if(isprime(d), print1(x, ", ") ) ) }
CROSSREFS
Sequence in context: A265885 A294994 A292205 * A181525 A082843 A162567
KEYWORD
easy,nonn
AUTHOR
Cino Hilliard, Nov 12 2005
STATUS
approved