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A089061
a(0) = 5, a(1) = 7; for n>1, a(n) = a(n-1)+a(n-2)-(2n-2).
0
5, 7, 10, 13, 17, 22, 29, 39, 54, 77, 113, 170, 261, 407, 642, 1021, 1633, 2622, 4221, 6807, 10990, 17757, 28705, 46418, 75077, 121447, 196474, 317869, 514289, 832102, 1346333, 2178375, 3524646, 5702957, 9227537, 14930426, 24157893
OFFSET
0,1
FORMULA
a(n) = Fibonacci(n+1)+2n+4. - Ralf Stephan, Feb 24 2004
MATHEMATICA
RecurrenceTable[{a[0]==5, a[1]==7, a[n]==a[n-1]+a[n-2]-(2n-2)}, a, {n, 40}] (* or *) LinearRecurrence[{3, -2, -1, 1}, {5, 7, 10, 13}, 40] (* Harvey P. Dale, Apr 23 2018 *)
CROSSREFS
Sequence in context: A287444 A196175 A112251 * A093115 A020936 A025074
KEYWORD
nonn
AUTHOR
STATUS
approved