%I #5 Mar 30 2012 17:27:33

%S 1,1,1,1,1,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,

%T 1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,2,1,2,1,2,1,1,1,1,0,1,1,1,

%U 2,2,2,4,5,4,3,4,5,3,4,3,4,3,4,3,1,3,0,3,1,3,1,4,5,4,5,3,4,5,3,4,3,4,3,4,3

%N a(n) = number of 'Reverse and Add!' operations that have to be applied to the n-th term of A063052 in order to obtain a term in the trajectory of 879.

%H <a href="/index/Res#RAA">Index entries for sequences related to Reverse and Add!</a>

%e 1497 is a term of A063052. One 'Reverse and Add!' operation applied to 1497 leads to a term (9438) in the trajectory of 879, so the corresponding term of the present sequence is 1.

%Y A023108, A033865, A063051, A063052.

%K base,nonn

%O 0,56

%A _Klaus Brockhaus_, Jul 07 2001