OFFSET
1,1
COMMENTS
The expression n^2*(n+1)!/(n^tau(n)) is always an integer. n^tau(n) is also the product of square divisors of n (cf. A062758).
LINKS
Amiram Eldar, Table of n, a(n) for n = 1..448
MATHEMATICA
a[n_] := (n+1)! / n^(DivisorSigma[0, n] - 2); Array[a, 23] (* Amiram Eldar, Aug 03 2024 *)
PROG
(PARI) a(n) = (n+1)! / n^(numdiv(n)-2); \\ Amiram Eldar, Aug 03 2024
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Benoit Cloitre, Apr 08 2002
EXTENSIONS
a(22)-a(23) from Amiram Eldar, Aug 03 2024
STATUS
approved