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a(n) = 2^n mod n^2.
11

%I #20 Dec 07 2024 14:55:48

%S 0,0,8,0,7,28,30,0,26,24,112,64,80,116,143,0,155,28,116,176,197,444,

%T 255,64,57,316,80,128,60,424,374,0,602,616,18,784,76,460,944,576,207,

%U 1324,303,1600,782,1016,1929,1792,2382,124,1844,2512,1009,568,1693,704

%N a(n) = 2^n mod n^2.

%H Alois P. Heinz, <a href="/A066606/b066606.txt">Table of n, a(n) for n = 1..10000</a> (first 1000 terms from Harry J. Smith)

%e a(7) = 30 as 2^7 = 128 = (7^2)*2 + 30.

%p a:= n-> 2&^n mod (n^2):

%p seq(a(n), n=1..100); # _Alois P. Heinz_, Jul 04 2017

%t Table[PowerMod[2,n,n^2],{n,60}] (* _Harvey P. Dale_, Dec 08 2015 *)

%o (PARI) a(n) = { lift(Mod(2, n^2)^n) } \\ _Harry J. Smith_, Mar 10 2010

%K easy,nonn,changed

%O 1,3

%A _Amarnath Murthy_, Dec 22 2001

%E More terms from _Floor van Lamoen_ and _Robert G. Wilson v_, Dec 23 2001