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a(n) = (9*n + 4)^11.
1

%I #12 Sep 08 2022 08:44:42

%S 4194304,1792160394037,584318301411328,25408476896404831,

%T 419430400000000000,3909821048582988049,24986644000165537792,

%U 122130132904968017083,488595558857835544576,1673432436896142578125

%N a(n) = (9*n + 4)^11.

%H Vincenzo Librandi, <a href="/A017219/b017219.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_12">Index entries for linear recurrences with constant coefficients</a>, signature (12, -66, 220, -495, 792, -924, 792, -495, 220, -66, 12, -1).

%o (Magma) [(9*n+4)^11: n in [0..15]]; // _Vincenzo Librandi_, Jul 24 2011

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_