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Iridium tetrafluoride

(Redirected from Iridium(IV) fluoride)

Iridium(IV) fluoride is a chemical compound of iridium and fluorine, with the chemical formula IrF4 and is a dark brown solid.[1] Early reports of IrF4 prior to 1965 are questionable and appear to describe the compound IrF5.[1] The solid can be prepared by reduction of IrF5 with iridium black[1] or reduction with H2 in aqueous HF.[2] The crystal structure of the solid is notable as it was the first example of a three-dimensional lattice structure found for a metal tetrafluoride and subsequently RhF4, PdF4 and PtF4 have been found to have the same structure.[3] The structure has 6 coordinate, octahedral, iridium where two edges of the octahedra are shared and the two unshared fluorine atoms are cis to one another.[3]

Iridium(IV) fluoride
Names
Other names
Iridium tetrafluoride
Identifiers
3D model (JSmol)
  • InChI=1S/4FH.Ir/h4*1H;/q;;;;+4/p-4
    Key: WOJCGZMITDEZTA-UHFFFAOYSA-J
  • F[Ir](F)(F)F
Properties
IrF4
Molar mass 268.2109 g/mol
Appearance dark brown solid
Related compounds
Other anions
iridium dioxide
Other cations
sodium fluoride, potassium fluoride, caesium fluoride, calcium fluoride
Related compounds
iridium(V) fluoride
iridium(VI) fluoride
rhodium(IV) fluoride
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
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References

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  1. ^ a b c Greenwood, Norman N.; Earnshaw, Alan (1997). Chemistry of the Elements (2nd ed.). Butterworth-Heinemann. ISBN 978-0-08-037941-8.
  2. ^ Paine, Robert T.; Asprey, Larned B. (1975). "Reductive syntheses of transition metal fluoride compounds. Synthesis of rhenium, osmium, and iridium pentafluorides and tetrafluorides". Inorg. Chem. 14 (5): 1111–1113. doi:10.1021/ic50147a030.
  3. ^ a b Wells A.F. (1984) Structural Inorganic Chemistry 5th edition Oxford Science Publications ISBN 0-19-855370-6