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2008 BCR Open Romania

(Redirected from 2008 Romanian Open)

The 2008 BCR Open Romania was a men's tennis tournament played on outdoor clay courts. It was the 16th edition of the event known that year as the BCR Open Romania, and was part of the International Series of the 2008 ATP Tour. It took place at the Arenele BNR in Bucharest, Romania, from 8 September through 14 September 2008.

2008 BCR Open Romania
Date8–14 September
Edition16th
CategoryInternational Series
Draw32S / 16D
Prize money€349,000
SurfaceClay / outdoor
LocationBucharest, Romania
VenueArenele BNR
Champions
Singles
France Gilles Simon[1]
Doubles
France Nicolas Devilder / France Paul-Henri Mathieu[2]
← 2007 · BCR Open Romania · 2009 →

The singles field was led by ATP No. 12, Stuttgart runner-up, Canada Masters quarterfinalist Richard Gasquet, Casablanca and Indianapolis titlist, and Bucharest defending champion Gilles Simon, and Costa do Sauípe and Acapulco winner, Valencia finalist Nicolás Almagro. Other seeded players were Marseille and Munich semifinalist Paul-Henri Mathieu, French Open quarterfinalist Ernests Gulbis, Carlos Moyá, Marcel Granollers and José Acasuso.

Second-seeded and defending champion Gilles Simon won the singles title.

Finals

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Singles

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France  Gilles Simon defeated Spain  Carlos Moyá, 6–3, 6–4

  • It was Gilles Simon's 3rd title of the year, and his 5th overall. It was his 2nd consecutive win at the event.

Doubles

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France  Nicolas Devilder / France  Paul-Henri Mathieu defeated Poland  Mariusz Fyrstenberg / Poland  Marcin Matkowski, 7–6(7–4), 6–7(9–11), [22–20]

References

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  1. ^ "2008 Bucharest – Singles draw". Association of Tennis Professionals (ATP).
  2. ^ "2008 Bucharest – Doubles draw". Association of Tennis Professionals (ATP).
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