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80347481 is a prime number
BaseRepresentation
bin1001100101000…
…00000101011001
312121012002000122
410302200011121
5131032104411
611550043025
71663641134
oct462400531
9177162018
1080347481
1141399285
1222aa9475
13138525b6
14a95721b
1570c19db
hex4ca0159

80347481 has 2 divisors, whose sum is σ = 80347482. Its totient is φ = 80347480.

The previous prime is 80347433. The next prime is 80347493. The reversal of 80347481 is 18474308.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 65869456 + 14478025 = 8116^2 + 3805^2 .

It is a cyclic number.

It is not a de Polignac number, because 80347481 - 210 = 80346457 is a prime.

It is a super-2 number, since 2×803474812 = 12911435406090722, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (80347781) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40173740 + 40173741.

It is an arithmetic number, because the mean of its divisors is an integer number (40173741).

Almost surely, 280347481 is an apocalyptic number.

It is an amenable number.

80347481 is a deficient number, since it is larger than the sum of its proper divisors (1).

80347481 is an equidigital number, since it uses as much as digits as its factorization.

80347481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21504, while the sum is 35.

The square root of 80347481 is about 8963.6756411642. The cubic root of 80347481 is about 431.5098912072.

It can be divided in two parts, 803 and 47481, that added together give a palindrome (48284).

The spelling of 80347481 in words is "eighty million, three hundred forty-seven thousand, four hundred eighty-one".