[go: up one dir, main page]

Search a number
-
+
537968640 = 2143511199
BaseRepresentation
bin100000000100001…
…100000000000000
31101111021122020110
4200010030000000
52100204444030
6125214311320
716221441456
oct4004140000
91344248213
10537968640
1125673a890
121301b8540
13875ba151
145163a9d6
15323681b0
hex2010c000

537968640 has 240 divisors, whose sum is σ = 1887379200. Its totient is φ = 129761280.

The previous prime is 537968593. The next prime is 537968653. The reversal of 537968640 is 46869735.

It is a tau number, because it is divible by the number of its divisors (240).

It is a Harshad number since it is a multiple of its sum of digits (48).

It is a self number, because there is not a number n which added to its sum of digits gives 537968640.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2703261 + ... + 2703459.

It is an arithmetic number, because the mean of its divisors is an integer number (7864080).

Almost surely, 2537968640 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 537968640, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (943689600).

537968640 is an abundant number, since it is smaller than the sum of its proper divisors (1349410560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

537968640 is a wasteful number, since it uses less digits than its factorization.

537968640 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 246 (or 220 counting only the distinct ones).

The product of its (nonzero) digits is 1088640, while the sum is 48.

The square root of 537968640 is about 23194.1509868329. The cubic root of 537968640 is about 813.3028983207.

The spelling of 537968640 in words is "five hundred thirty-seven million, nine hundred sixty-eight thousand, six hundred forty".