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53400101 is a prime number
BaseRepresentation
bin1100101110110…
…1001000100101
310201111000011112
43023231020211
5102132300401
65144314405
71215615266
oct313551045
9121430145
1053400101
1128163317
1215a72a05
13b0a8bc1
14714096d
154a4c3bb
hex32ed225

53400101 has 2 divisors, whose sum is σ = 53400102. Its totient is φ = 53400100.

The previous prime is 53400079. The next prime is 53400103. The reversal of 53400101 is 10100435.

53400101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 50836900 + 2563201 = 7130^2 + 1601^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53400101 is a prime.

Together with 53400103, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53400103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26700050 + 26700051.

It is an arithmetic number, because the mean of its divisors is an integer number (26700051).

Almost surely, 253400101 is an apocalyptic number.

It is an amenable number.

53400101 is a deficient number, since it is larger than the sum of its proper divisors (1).

53400101 is an equidigital number, since it uses as much as digits as its factorization.

53400101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 14.

The square root of 53400101 is about 7307.5372732542. The cubic root of 53400101 is about 376.5714229998.

Adding to 53400101 its reverse (10100435), we get a palindrome (63500536).

The spelling of 53400101 in words is "fifty-three million, four hundred thousand, one hundred one".