53400001 has 2 divisors, whose sum is σ = 53400002. Its totient is φ = 53400000.

The previous prime is 53399981. The next prime is 53400059. The reversal of 53400001 is 10000435.

53400001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 51840000 + 1560001 = 7200^2 + 1249^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-53400001 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (53400101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26700000 + 26700001.

It is an arithmetic number, because the mean of its divisors is an integer number (26700001).

Almost surely, 2^53400001 is an apocalyptic number.

It is an amenable number.

53400001 is a deficient number, since it is larger than the sum of its proper divisors (1).

53400001 is an equidigital number, since it uses as much as digits as its factorization.

53400001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 13.

The square root of 53400001 is about 7307.5304310006. The cubic root of 53400001 is about 376.5711879368.

Adding to 53400001 its reverse (10000435), we get a palindrome (63400436).

The spelling of 53400001 in words is "fifty-three million, four hundred thousand, one".