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53120131 = 479911069
BaseRepresentation
bin1100101010100…
…0110010000011
310200221210010021
43022220302003
5102044321011
65134314311
71213341121
oct312506203
9120853107
1053120131
1127a91a39
1215958997
13b00b63c
1470aa911
1549e4471
hex32a8c83

53120131 has 4 divisors (see below), whose sum is σ = 53136000. Its totient is φ = 53104264.

The previous prime is 53120117. The next prime is 53120173. The reversal of 53120131 is 13102135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53120131 - 25 = 53120099 is a prime.

It is a super-2 number, since 2×531201312 = 5643496634914322, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53120191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 736 + ... + 10333.

It is an arithmetic number, because the mean of its divisors is an integer number (13284000).

Almost surely, 253120131 is an apocalyptic number.

53120131 is a deficient number, since it is larger than the sum of its proper divisors (15869).

53120131 is a wasteful number, since it uses less digits than its factorization.

53120131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15868.

The product of its (nonzero) digits is 90, while the sum is 16.

The square root of 53120131 is about 7288.3558502587. The cubic root of 53120131 is about 375.9121640118.

Adding to 53120131 its reverse (13102135), we get a palindrome (66222266).

The spelling of 53120131 in words is "fifty-three million, one hundred twenty thousand, one hundred thirty-one".

Divisors: 1 4799 11069 53120131