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5143500403 is a prime number
BaseRepresentation
bin1001100101001001…
…11001011001110011
3111021110101220002221
410302210321121303
541013214003103
62210215021511
7241314013666
oct46244713163
914243356087
105143500403
1121aa40aa88
12bb666a897
1363c7c3282
1436b1776dd
152018501bd
hex132939673

5143500403 has 2 divisors, whose sum is σ = 5143500404. Its totient is φ = 5143500402.

The previous prime is 5143500347. The next prime is 5143500457. The reversal of 5143500403 is 3040053415.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5143500403 - 221 = 5141403251 is a prime.

It is a super-2 number, since 2×51435004032 = 52911192791322324818, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5143500473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2571750201 + 2571750202.

It is an arithmetic number, because the mean of its divisors is an integer number (2571750202).

Almost surely, 25143500403 is an apocalyptic number.

5143500403 is a deficient number, since it is larger than the sum of its proper divisors (1).

5143500403 is an equidigital number, since it uses as much as digits as its factorization.

5143500403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3600, while the sum is 25.

The square root of 5143500403 is about 71718.2013368991. The cubic root of 5143500403 is about 1726.1807112785.

Adding to 5143500403 its reverse (3040053415), we get a palindrome (8183553818).

The spelling of 5143500403 in words is "five billion, one hundred forty-three million, five hundred thousand, four hundred three".