Base | Representation |
---|---|
bin | 1100001101011… |
… | …1011010111011 |
3 | 10120100221102020 |
4 | 3003113122323 |
5 | 101102322021 |
6 | 5025405523 |
7 | 1161211662 |
oct | 303273273 |
9 | 116327366 |
10 | 51214011 |
11 | 269aa932 |
12 | 151998a3 |
13 | a7c1b64 |
14 | 6b31dd9 |
15 | 47697c6 |
hex | 30d76bb |
51214011 has 4 divisors (see below), whose sum is σ = 68285352. Its totient is φ = 34142672.
The previous prime is 51214003. The next prime is 51214021. The reversal of 51214011 is 11041215.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51214011 - 23 = 51214003 is a prime.
It is not an unprimeable number, because it can be changed into a prime (51214001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8535666 + ... + 8535671.
It is an arithmetic number, because the mean of its divisors is an integer number (17071338).
Almost surely, 251214011 is an apocalyptic number.
51214011 is a deficient number, since it is larger than the sum of its proper divisors (17071341).
51214011 is a wasteful number, since it uses less digits than its factorization.
51214011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17071340.
The product of its (nonzero) digits is 40, while the sum is 15.
The square root of 51214011 is about 7156.3965094173. The cubic root of 51214011 is about 371.3609751108.
Adding to 51214011 its reverse (11041215), we get a palindrome (62255226).
The spelling of 51214011 in words is "fifty-one million, two hundred fourteen thousand, eleven".
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