Base | Representation |
---|---|
bin | 1001100001100001… |
… | …01000111010010001 |
3 | 111012100001112112122 |
4 | 10300300220322101 |
5 | 40432413233040 |
6 | 2203205504025 |
7 | 240463662635 |
oct | 46060507221 |
9 | 14170045478 |
10 | 5113024145 |
11 | 2194194799 |
12 | ba8412015 |
13 | 6363b2598 |
14 | 3670c2dc5 |
15 | 1edd301b5 |
hex | 130c28e91 |
5113024145 has 4 divisors (see below), whose sum is σ = 6135628980. Its totient is φ = 4090419312.
The previous prime is 5113024139. The next prime is 5113024207. The reversal of 5113024145 is 5414203115.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1946486161 + 3166537984 = 44119^2 + 56272^2 .
It is a cyclic number.
It is not a de Polignac number, because 5113024145 - 214 = 5113007761 is a prime.
It is a super-2 number, since 2×51130241452 = 52286031814705962050, which contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 511302410 + ... + 511302419.
It is an arithmetic number, because the mean of its divisors is an integer number (1533907245).
Almost surely, 25113024145 is an apocalyptic number.
It is an amenable number.
5113024145 is a deficient number, since it is larger than the sum of its proper divisors (1022604835).
5113024145 is a wasteful number, since it uses less digits than its factorization.
5113024145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1022604834.
The product of its (nonzero) digits is 2400, while the sum is 26.
The square root of 5113024145 is about 71505.4133964695. The cubic root of 5113024145 is about 1722.7646345924.
The spelling of 5113024145 in words is "five billion, one hundred thirteen million, twenty-four thousand, one hundred forty-five".
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