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5110044431 is a prime number
BaseRepresentation
bin1001100001001010…
…10001011100001111
3111012010110011010212
410300211101130033
540431132410211
62203021553035
7240426442502
oct46045213417
914163404125
105110044431
11219253a018
12ba741577b
136358ab23b
14366949139
151ed94238b
hex13095170f

5110044431 has 2 divisors, whose sum is σ = 5110044432. Its totient is φ = 5110044430.

The previous prime is 5110044409. The next prime is 5110044451. The reversal of 5110044431 is 1344400115.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5110044431 - 218 = 5109782287 is a prime.

It is a super-2 number, since 2×51100444312 = 52225108173588227522, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5110044397 and 5110044406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5110044451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2555022215 + 2555022216.

It is an arithmetic number, because the mean of its divisors is an integer number (2555022216).

Almost surely, 25110044431 is an apocalyptic number.

5110044431 is a deficient number, since it is larger than the sum of its proper divisors (1).

5110044431 is an equidigital number, since it uses as much as digits as its factorization.

5110044431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 960, while the sum is 23.

The square root of 5110044431 is about 71484.5747766607. The cubic root of 5110044431 is about 1722.4299113925.

Adding to 5110044431 its reverse (1344400115), we get a palindrome (6454444546).

The spelling of 5110044431 in words is "five billion, one hundred ten million, forty-four thousand, four hundred thirty-one".