Base | Representation |
---|---|
bin | 1100000011010… |
… | …1100010011111 |
3 | 10112010020212011 |
4 | 3000311202133 |
5 | 100420112233 |
6 | 5003252051 |
7 | 1152450562 |
oct | 300654237 |
9 | 115106764 |
10 | 50550943 |
11 | 26597743 |
12 | 14b1a027 |
13 | a61c101 |
14 | 69dc4d9 |
15 | 46880cd |
hex | 303589f |
50550943 has 2 divisors, whose sum is σ = 50550944. Its totient is φ = 50550942.
The previous prime is 50550919. The next prime is 50550949. The reversal of 50550943 is 34905505.
50550943 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50550943 is a prime.
It is a super-3 number, since 3×505509433 (a number of 24 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50550949) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25275471 + 25275472.
It is an arithmetic number, because the mean of its divisors is an integer number (25275472).
Almost surely, 250550943 is an apocalyptic number.
50550943 is a deficient number, since it is larger than the sum of its proper divisors (1).
50550943 is an equidigital number, since it uses as much as digits as its factorization.
50550943 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13500, while the sum is 31.
The square root of 50550943 is about 7109.9186352588. The cubic root of 50550943 is about 369.7513376693.
The spelling of 50550943 in words is "fifty million, five hundred fifty thousand, nine hundred forty-three".
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