55109993 has 2 divisors, whose sum is σ = 55109994. Its totient is φ = 55109992.

The previous prime is 55109969. The next prime is 55110037. The reversal of 55109993 is 39990155.

55109993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 54715609 + 394384 = 7397^2 + 628^2 .

It is a cyclic number.

It is not a de Polignac number, because 55109993 - 2⁸ = 55109737 is a prime.

It is a super-2 number, since 2×55109993² = 6074222656920098, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 55109993.

It is not a weakly prime, because it can be changed into another prime (55109693) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27554996 + 27554997.

It is an arithmetic number, because the mean of its divisors is an integer number (27554997).

Almost surely, 2^55109993 is an apocalyptic number.

It is an amenable number.

55109993 is a deficient number, since it is larger than the sum of its proper divisors (1).

55109993 is an equidigital number, since it uses as much as digits as its factorization.

55109993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54675, while the sum is 41.

The square root of 55109993 is about 7423.6105097183. The cubic root of 55109993 is about 380.5485912954.

The spelling of 55109993 in words is "fifty-five million, one hundred nine thousand, nine hundred ninety-three".