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54730113 = 318243371
BaseRepresentation
bin1101000011000…
…1110110000001
310210222120121020
43100301312001
5103002330423
65233020053
71233125004
oct320616601
9123876536
1054730113
11289915a9
12163b4629
13b4533a9
1473a953b
154c114e3
hex3431d81

54730113 has 4 divisors (see below), whose sum is σ = 72973488. Its totient is φ = 36486740.

The previous prime is 54730103. The next prime is 54730129. The reversal of 54730113 is 31103745.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 54730113 - 210 = 54729089 is a prime.

It is not an unprimeable number, because it can be changed into a prime (54730103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9121683 + ... + 9121688.

It is an arithmetic number, because the mean of its divisors is an integer number (18243372).

Almost surely, 254730113 is an apocalyptic number.

It is an amenable number.

54730113 is a deficient number, since it is larger than the sum of its proper divisors (18243375).

54730113 is a wasteful number, since it uses less digits than its factorization.

54730113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18243374.

The product of its (nonzero) digits is 1260, while the sum is 24.

The square root of 54730113 is about 7397.9803324962. The cubic root of 54730113 is about 379.6721849671.

Adding to 54730113 its reverse (31103745), we get a palindrome (85833858).

The spelling of 54730113 in words is "fifty-four million, seven hundred thirty thousand, one hundred thirteen".

Divisors: 1 3 18243371 54730113