4225401331 has 2 divisors, whose sum is σ = 4225401332. Its totient is φ = 4225401330.

The previous prime is 4225401319. The next prime is 4225401409. The reversal of 4225401331 is 1331045224.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4225401331 is a prime.

It is a super-2 number, since 2×4225401331² = 35708032816033143122, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4225401296 and 4225401305.

It is not a weakly prime, because it can be changed into another prime (4225408331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2112700665 + 2112700666.

It is an arithmetic number, because the mean of its divisors is an integer number (2112700666).

Almost surely, 2^4225401331 is an apocalyptic number.

4225401331 is a deficient number, since it is larger than the sum of its proper divisors (1).

4225401331 is an equidigital number, since it uses as much as digits as its factorization.

4225401331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 25.

The square root of 4225401331 is about 65003.0870882299. The cubic root of 4225401331 is about 1616.6747484250.

Adding to 4225401331 its reverse (1331045224), we get a palindrome (5556446555).

The spelling of 4225401331 in words is "four billion, two hundred twenty-five million, four hundred one thousand, three hundred thirty-one".