413050433 has 2 divisors, whose sum is σ = 413050434. Its totient is φ = 413050432.

The previous prime is 413050427. The next prime is 413050439. The reversal of 413050433 is 334050314.

It is a balanced prime because it is at equal distance from previous prime (413050427) and next prime (413050439).

It can be written as a sum of positive squares in only one way, i.e., 287879089 + 125171344 = 16967^2 + 11188^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-413050433 is a prime.

It is a super-2 number, since 2×413050433² = 341221320402974978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 413050399 and 413050408.

It is not a weakly prime, because it can be changed into another prime (413050439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206525216 + 206525217.

It is an arithmetic number, because the mean of its divisors is an integer number (206525217).

Almost surely, 2^413050433 is an apocalyptic number.

It is an amenable number.

413050433 is a deficient number, since it is larger than the sum of its proper divisors (1).

413050433 is an equidigital number, since it uses as much as digits as its factorization.

413050433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 23.

The square root of 413050433 is about 20323.6422178703. The cubic root of 413050433 is about 744.7337354561.

The spelling of 413050433 in words is "four hundred thirteen million, fifty thousand, four hundred thirty-three".