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411214103 = 1351330431
BaseRepresentation
bin11000100000101…
…010000100010111
31001122202211200222
4120200222010113
51320232322403
6104445424555
713122155636
oct3040520427
91048684628
10411214103
111a1135273
12b586b15b
1367269971
143c88351d
152617b338
hex1882a117

411214103 has 4 divisors (see below), whose sum is σ = 411258048. Its totient is φ = 411170160.

The previous prime is 411214091. The next prime is 411214147. The reversal of 411214103 is 301412114.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 411214103 - 214 = 411197719 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (411214303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1703 + ... + 28728.

It is an arithmetic number, because the mean of its divisors is an integer number (102814512).

Almost surely, 2411214103 is an apocalyptic number.

411214103 is a deficient number, since it is larger than the sum of its proper divisors (43945).

411214103 is a wasteful number, since it uses less digits than its factorization.

411214103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43944.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 411214103 is about 20278.4147062831. The cubic root of 411214103 is about 743.6284559239.

Adding to 411214103 its reverse (301412114), we get a palindrome (712626217).

The spelling of 411214103 in words is "four hundred eleven million, two hundred fourteen thousand, one hundred three".

Divisors: 1 13513 30431 411214103