411133013 has 4 divisors (see below), whose sum is σ = 411173568. Its totient is φ = 411092460.

The previous prime is 411132989. The next prime is 411133033. The reversal of 411133013 is 310331114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 310331114 = 2 ⋅155165557.

It is a cyclic number.

It is not a de Polignac number, because 411133013 - 2¹⁰ = 411131989 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 411132982 and 411133000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (411133033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9908 + ... + 30338.

It is an arithmetic number, because the mean of its divisors is an integer number (102793392).

Almost surely, 2^411133013 is an apocalyptic number.

It is an amenable number.

411133013 is a deficient number, since it is larger than the sum of its proper divisors (40555).

411133013 is a wasteful number, since it uses less digits than its factorization.

411133013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40554.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 411133013 is about 20276.4151910539. The cubic root of 411133013 is about 743.5795723900.

Adding to 411133013 its reverse (310331114), we get a palindrome (721464127).

The spelling of 411133013 in words is "four hundred eleven million, one hundred thirty-three thousand, thirteen".