4011225131 has 2 divisors, whose sum is σ = 4011225132. Its totient is φ = 4011225130.

The previous prime is 4011225121. The next prime is 4011225133. The reversal of 4011225131 is 1315221104.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4011225131 - 2²² = 4007030827 is a prime.

It is a super-2 number, since 2×4011225131² = 32179854103131934322, which contains 22 as substring.

Together with 4011225133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4011225133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2005612565 + 2005612566.

It is an arithmetic number, because the mean of its divisors is an integer number (2005612566).

Almost surely, 2^4011225131 is an apocalyptic number.

4011225131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4011225131 is an equidigital number, since it uses as much as digits as its factorization.

4011225131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 20.

The square root of 4011225131 is about 63334.2334839540. The cubic root of 4011225131 is about 1588.8845638443.

Adding to 4011225131 its reverse (1315221104), we get a palindrome (5326446235).

The spelling of 4011225131 in words is "four billion, eleven million, two hundred twenty-five thousand, one hundred thirty-one".