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3111141221 is a prime number
BaseRepresentation
bin1011100101110000…
…0011111101100101
322000211011100102122
42321130003331211
522332423004341
61232414315325
7140045156366
oct27134037545
98024140378
103111141221
1113571814a1
12729ab8b45
133a7729186
14217297b6d
151331e994b
hexb9703f65

3111141221 has 2 divisors, whose sum is σ = 3111141222. Its totient is φ = 3111141220.

The previous prime is 3111141217. The next prime is 3111141223. The reversal of 3111141221 is 1221411113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2957728225 + 153412996 = 54385^2 + 12386^2 .

It is a cyclic number.

It is not a de Polignac number, because 3111141221 - 22 = 3111141217 is a prime.

Together with 3111141223, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3111141221.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3111141223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555570610 + 1555570611.

It is an arithmetic number, because the mean of its divisors is an integer number (1555570611).

Almost surely, 23111141221 is an apocalyptic number.

It is an amenable number.

3111141221 is a deficient number, since it is larger than the sum of its proper divisors (1).

3111141221 is an equidigital number, since it uses as much as digits as its factorization.

3111141221 is an evil number, because the sum of its binary digits is even.

The product of its digits is 48, while the sum is 17.

The square root of 3111141221 is about 55777.6050131233. The cubic root of 3111141221 is about 1459.8444228106.

Adding to 3111141221 its reverse (1221411113), we get a palindrome (4332552334).

The spelling of 3111141221 in words is "three billion, one hundred eleven million, one hundred forty-one thousand, two hundred twenty-one".