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215442113 = 1032091671
BaseRepresentation
bin11001101011101…
…10001011000001
3120000101121000112
430311312023001
5420123121423
633213401105
75224141055
oct1465661301
9500347015
10215442113
1110067a937
1260199195
1335832c53
1420881c65
1513da9a78
hexcd762c1

215442113 has 4 divisors (see below), whose sum is σ = 217533888. Its totient is φ = 213350340.

The previous prime is 215442067. The next prime is 215442133. The reversal of 215442113 is 311244512.

215442113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 215442113 - 218 = 215179969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (215442133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1045733 + ... + 1045938.

It is an arithmetic number, because the mean of its divisors is an integer number (54383472).

Almost surely, 2215442113 is an apocalyptic number.

It is an amenable number.

215442113 is a deficient number, since it is larger than the sum of its proper divisors (2091775).

215442113 is a wasteful number, since it uses less digits than its factorization.

215442113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2091774.

The product of its digits is 960, while the sum is 23.

The square root of 215442113 is about 14677.9464844371. The cubic root of 215442113 is about 599.4829925965.

Adding to 215442113 its reverse (311244512), we get a palindrome (526686625).

The spelling of 215442113 in words is "two hundred fifteen million, four hundred forty-two thousand, one hundred thirteen".

Divisors: 1 103 2091671 215442113