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2143325157 = 3714441719
BaseRepresentation
bin111111111000000…
…1000101111100101
312112101001012101020
41333300020233211
513342142401112
6552402521353
7104053651251
oct17760105745
95471035336
102143325157
119aa93aa06
124b9966259
1328207a04c
14164927261
15c827448c
hex7fc08be5

2143325157 has 4 divisors (see below), whose sum is σ = 2857766880. Its totient is φ = 1428883436.

The previous prime is 2143325123. The next prime is 2143325189. The reversal of 2143325157 is 7515233412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2143325157 - 210 = 2143324133 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2143325117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 357220857 + ... + 357220862.

It is an arithmetic number, because the mean of its divisors is an integer number (714441720).

Almost surely, 22143325157 is an apocalyptic number.

It is an amenable number.

2143325157 is a deficient number, since it is larger than the sum of its proper divisors (714441723).

2143325157 is an equidigital number, since it uses as much as digits as its factorization.

2143325157 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 714441722.

The product of its digits is 25200, while the sum is 33.

The square root of 2143325157 is about 46296.0598431443. The cubic root of 2143325157 is about 1289.3258414821.

Adding to 2143325157 its reverse (7515233412), we get a palindrome (9658558569).

The spelling of 2143325157 in words is "two billion, one hundred forty-three million, three hundred twenty-five thousand, one hundred fifty-seven".

Divisors: 1 3 714441719 2143325157