[go: up one dir, main page]

Search a number
-
+
2540147 = 10332459
BaseRepresentation
bin1001101100001001110011
311210001102112
421230021303
51122241042
6130235535
730406451
oct11541163
94701375
102540147
1114854a5
12a25bab
136ac25c
144a19d1
15352982
hex26c273

2540147 has 4 divisors (see below), whose sum is σ = 2543640. Its totient is φ = 2536656.

The previous prime is 2540141. The next prime is 2540173. The reversal of 2540147 is 7410452.

2540147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 2540147 - 210 = 2539123 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2540141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 197 + ... + 2262.

It is an arithmetic number, because the mean of its divisors is an integer number (635910).

22540147 is an apocalyptic number.

2540147 is a deficient number, since it is larger than the sum of its proper divisors (3493).

2540147 is a wasteful number, since it uses less digits than its factorization.

2540147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3492.

The product of its (nonzero) digits is 1120, while the sum is 23.

The square root of 2540147 is about 1593.7838623854. The cubic root of 2540147 is about 136.4435310531.

Adding to 2540147 its reverse (7410452), we get a palindrome (9950599).

The spelling of 2540147 in words is "two million, five hundred forty thousand, one hundred forty-seven".

Divisors: 1 1033 2459 2540147