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2532505207 is a prime number
BaseRepresentation
bin1001011011110010…
…1111011001110111
320112111100121001011
42112330233121313
520141310131312
61055144213051
7116520640051
oct22674573167
96474317034
102532505207
11108a595711
125a816a187
133148a07bb
141a04b28d1
15ec4ebda7
hex96f2f677

2532505207 has 2 divisors, whose sum is σ = 2532505208. Its totient is φ = 2532505206.

The previous prime is 2532505141. The next prime is 2532505247. The reversal of 2532505207 is 7025052352.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2532505207 is a prime.

It is a super-2 number, since 2×25325052072 = 12827165246964225698, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2532505247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1266252603 + 1266252604.

It is an arithmetic number, because the mean of its divisors is an integer number (1266252604).

Almost surely, 22532505207 is an apocalyptic number.

2532505207 is a deficient number, since it is larger than the sum of its proper divisors (1).

2532505207 is an equidigital number, since it uses as much as digits as its factorization.

2532505207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21000, while the sum is 31.

The square root of 2532505207 is about 50324.0022951275. The cubic root of 2532505207 is about 1363.0656777675.

Adding to 2532505207 its reverse (7025052352), we get a palindrome (9557557559).

The spelling of 2532505207 in words is "two billion, five hundred thirty-two million, five hundred five thousand, two hundred seven".