[go: up one dir, main page]

Search a number
-
+
1395031481 is a prime number
BaseRepresentation
bin101001100100110…
…0111110110111001
310121012222221102122
41103021213312321
510324112001411
6350232211025
746366400114
oct12311476671
93535887378
101395031481
11656505888
1232b239a75
1319302c11c
14d33bb57b
15827129db
hex53267db9

1395031481 has 2 divisors, whose sum is σ = 1395031482. Its totient is φ = 1395031480.

The previous prime is 1395031453. The next prime is 1395031511. The reversal of 1395031481 is 1841305931.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 953821456 + 441210025 = 30884^2 + 21005^2 .

It is an emirp because it is prime and its reverse (1841305931) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1395031481 - 210 = 1395030457 is a prime.

It is a super-2 number, since 2×13950314812 = 3892225665962106722, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1395031081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 697515740 + 697515741.

It is an arithmetic number, because the mean of its divisors is an integer number (697515741).

Almost surely, 21395031481 is an apocalyptic number.

It is an amenable number.

1395031481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1395031481 is an equidigital number, since it uses as much as digits as its factorization.

1395031481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 35.

The square root of 1395031481 is about 37350.1202273835. The cubic root of 1395031481 is about 1117.3639860018.

The spelling of 1395031481 in words is "one billion, three hundred ninety-five million, thirty-one thousand, four hundred eighty-one".