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13671041 is a prime number
BaseRepresentation
bin110100001001…
…101010000001
3221201120010212
4310021222001
511444433131
61205003505
7224126156
oct64115201
927646125
1013671041
11779828a
1246b3595
132aa8797
141b5c22d
151300a2b
hexd09a81

13671041 has 2 divisors, whose sum is σ = 13671042. Its totient is φ = 13671040.

The previous prime is 13671011. The next prime is 13671113. The reversal of 13671041 is 14017631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8288641 + 5382400 = 2879^2 + 2320^2 .

It is a cyclic number.

It is not a de Polignac number, because 13671041 - 218 = 13408897 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13670998 and 13671016.

It is not a weakly prime, because it can be changed into another prime (13671011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6835520 + 6835521.

It is an arithmetic number, because the mean of its divisors is an integer number (6835521).

Almost surely, 213671041 is an apocalyptic number.

It is an amenable number.

13671041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13671041 is an equidigital number, since it uses as much as digits as its factorization.

13671041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

The square root of 13671041 is about 3697.4370853336. The cubic root of 13671041 is about 239.1115356232. Note that the first 3 decimals are identical.

Adding to 13671041 its reverse (14017631), we get a palindrome (27688672).

The spelling of 13671041 in words is "thirteen million, six hundred seventy-one thousand, forty-one".