Base | Representation |
---|---|
bin | 100111011011111… |
… | …0000111010101101 |
3 | 10102012220121120212 |
4 | 1032313300322231 |
5 | 10202222204013 |
6 | 335145352205 |
7 | 44535235604 |
oct | 11667607255 |
9 | 3365817525 |
10 | 1323241133 |
11 | 619a31715 |
12 | 30b198665 |
13 | 1811b4726 |
14 | c7a50a3b |
15 | 7b2816a8 |
hex | 4edf0ead |
1323241133 has 2 divisors, whose sum is σ = 1323241134. Its totient is φ = 1323241132.
The previous prime is 1323241109. The next prime is 1323241141. The reversal of 1323241133 is 3311423231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1279707529 + 43533604 = 35773^2 + 6598^2 .
It is a cyclic number.
It is not a de Polignac number, because 1323241133 - 216 = 1323175597 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1323241099 and 1323241108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1323241433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661620566 + 661620567.
It is an arithmetic number, because the mean of its divisors is an integer number (661620567).
Almost surely, 21323241133 is an apocalyptic number.
It is an amenable number.
1323241133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323241133 is an equidigital number, since it uses as much as digits as its factorization.
1323241133 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1296, while the sum is 23.
The square root of 1323241133 is about 36376.3815270293. The cubic root of 1323241133 is about 1097.8584042965.
Adding to 1323241133 its reverse (3311423231), we get a palindrome (4634664364).
The spelling of 1323241133 in words is "one billion, three hundred twenty-three million, two hundred forty-one thousand, one hundred thirty-three".
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