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132220113 = 344073371
BaseRepresentation
bin1111110000110…
…00010011010001
3100012210110220020
413320120103101
5232322020423
621041534053
73163565244
oct770302321
9305713806
10132220113
11686a8a23
1238344329
132151516c
14137bb25b
15b91b4e3
hex7e184d1

132220113 has 4 divisors (see below), whose sum is σ = 176293488. Its totient is φ = 88146740.

The previous prime is 132220063. The next prime is 132220117. The reversal of 132220113 is 311022231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132220113 - 216 = 132154577 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132220092 and 132220101.

It is not an unprimeable number, because it can be changed into a prime (132220117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22036683 + ... + 22036688.

It is an arithmetic number, because the mean of its divisors is an integer number (44073372).

Almost surely, 2132220113 is an apocalyptic number.

It is an amenable number.

132220113 is a deficient number, since it is larger than the sum of its proper divisors (44073375).

132220113 is an equidigital number, since it uses as much as digits as its factorization.

132220113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44073374.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 132220113 is about 11498.7004917947. The cubic root of 132220113 is about 509.4471941685.

Adding to 132220113 its reverse (311022231), we get a palindrome (443242344).

The spelling of 132220113 in words is "one hundred thirty-two million, two hundred twenty thousand, one hundred thirteen".

Divisors: 1 3 44073371 132220113