130411315 has 4 divisors (see below), whose sum is σ = 156493584. Its totient is φ = 104329048.

The previous prime is 130411313. The next prime is 130411349. The reversal of 130411315 is 513114031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 513114031 = 131 ⋅3916901.

It is a cyclic number.

It is not a de Polignac number, because 130411315 - 2¹ = 130411313 is a prime.

It is a super-2 number, since 2×130411315² = 34014222160058450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130411292 and 130411301.

It is not an unprimeable number, because it can be changed into a prime (130411313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13041127 + ... + 13041136.

It is an arithmetic number, because the mean of its divisors is an integer number (39123396).

Almost surely, 2^130411315 is an apocalyptic number.

130411315 is a deficient number, since it is larger than the sum of its proper divisors (26082269).

130411315 is an equidigital number, since it uses as much as digits as its factorization.

130411315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26082268.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 130411315 is about 11419.7773621030. Note that the first 3 decimals coincide. The cubic root of 130411315 is about 507.1134056635.

Adding to 130411315 its reverse (513114031), we get a palindrome (643525346).

The spelling of 130411315 in words is "one hundred thirty million, four hundred eleven thousand, three hundred fifteen".