Base | Representation |
---|---|
bin | 100110110111010… |
… | …0001110000000111 |
3 | 10100212210020000111 |
4 | 1031232201300013 |
5 | 10132313330003 |
6 | 333222053451 |
7 | 44213115121 |
oct | 11556416007 |
9 | 3325706014 |
10 | 1304042503 |
11 | 60a109485 |
12 | 30487a287 |
13 | 17a221caa |
14 | c5294211 |
15 | 7973ce6d |
hex | 4dba1c07 |
1304042503 has 4 divisors (see below), whose sum is σ = 1306303120. Its totient is φ = 1301781888.
The previous prime is 1304042479. The next prime is 1304042563. The reversal of 1304042503 is 3052404031.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3052404031 = 19913 ⋅153287.
It is a cyclic number.
It is not a de Polignac number, because 1304042503 - 217 = 1303911431 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1304042563) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1129443 + ... + 1130596.
It is an arithmetic number, because the mean of its divisors is an integer number (326575780).
Almost surely, 21304042503 is an apocalyptic number.
1304042503 is a deficient number, since it is larger than the sum of its proper divisors (2260617).
1304042503 is an equidigital number, since it uses as much as digits as its factorization.
1304042503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2260616.
The product of its (nonzero) digits is 1440, while the sum is 22.
The square root of 1304042503 is about 36111.5286716029. The cubic root of 1304042503 is about 1092.5229840148.
Adding to 1304042503 its reverse (3052404031), we get a palindrome (4356446534).
The spelling of 1304042503 in words is "one billion, three hundred four million, forty-two thousand, five hundred three".
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