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1301000215 = 5260200043
BaseRepresentation
bin100110110001011…
…1011000000010111
310100200001122210011
41031202323000113
510131024001330
6333032541051
744145214354
oct11542730027
93320048704
101301000215
11608420799
12303851787
131796c8318
14c4b0162b
157933b82a
hex4d8bb017

1301000215 has 4 divisors (see below), whose sum is σ = 1561200264. Its totient is φ = 1040800168.

The previous prime is 1301000213. The next prime is 1301000227. The reversal of 1301000215 is 5120001031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1301000215 - 21 = 1301000213 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1301000195 and 1301000204.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1301000213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130100017 + ... + 130100026.

It is an arithmetic number, because the mean of its divisors is an integer number (390300066).

Almost surely, 21301000215 is an apocalyptic number.

1301000215 is a deficient number, since it is larger than the sum of its proper divisors (260200049).

1301000215 is an equidigital number, since it uses as much as digits as its factorization.

1301000215 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 260200048.

The product of its (nonzero) digits is 30, while the sum is 13.

The square root of 1301000215 is about 36069.3805741102. The cubic root of 1301000215 is about 1091.6727158015.

Adding to 1301000215 its reverse (5120001031), we get a palindrome (6421001246).

The spelling of 1301000215 in words is "one billion, three hundred one million, two hundred fifteen", and thus it is an aban number.

Divisors: 1 5 260200043 1301000215