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12996433 is a prime number
BaseRepresentation
bin110001100100…
…111101010001
3220110021202101
4301210331101
511311341213
61142320401
7215316322
oct61447521
926407671
1012996433
11737745a
124429101
1329006c8
141a24449
15121abdd
hexc64f51

12996433 has 2 divisors, whose sum is σ = 12996434. Its totient is φ = 12996432.

The previous prime is 12996421. The next prime is 12996457. The reversal of 12996433 is 33469921.

12996433 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8928144 + 4068289 = 2988^2 + 2017^2 .

It is a cyclic number.

It is not a de Polignac number, because 12996433 - 217 = 12865361 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12996392 and 12996401.

It is not a weakly prime, because it can be changed into another prime (12996413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6498216 + 6498217.

It is an arithmetic number, because the mean of its divisors is an integer number (6498217).

Almost surely, 212996433 is an apocalyptic number.

It is an amenable number.

12996433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12996433 is an equidigital number, since it uses as much as digits as its factorization.

12996433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 34992, while the sum is 37.

The square root of 12996433 is about 3605.0565876280. The cubic root of 12996433 is about 235.1119611360. Note that the first 3 decimals are identical.

The spelling of 12996433 in words is "twelve million, nine hundred ninety-six thousand, four hundred thirty-three".