Base | Representation |
---|---|
bin | 101110010001… |
… | …011011010111 |
3 | 211211021020112 |
4 | 232101123113 |
5 | 11101130012 |
6 | 1111553235 |
7 | 205050311 |
oct | 56213327 |
9 | 24737215 |
10 | 12130007 |
11 | 69354aa |
12 | 408b81b |
13 | 2689226 |
14 | 187a7b1 |
15 | 10e9122 |
hex | b916d7 |
12130007 has 2 divisors, whose sum is σ = 12130008. Its totient is φ = 12130006.
The previous prime is 12130003. The next prime is 12130049. The reversal of 12130007 is 70003121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12130007 - 22 = 12130003 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 12129973 and 12130000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12130003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065003 + 6065004.
It is an arithmetic number, because the mean of its divisors is an integer number (6065004).
Almost surely, 212130007 is an apocalyptic number.
12130007 is a deficient number, since it is larger than the sum of its proper divisors (1).
12130007 is an equidigital number, since it uses as much as digits as its factorization.
12130007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42, while the sum is 14.
The square root of 12130007 is about 3482.8159583877. The cubic root of 12130007 is about 229.7666631689.
Adding to 12130007 its reverse (70003121), we get a palindrome (82133128).
The spelling of 12130007 in words is "twelve million, one hundred thirty thousand, seven".
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