Base | Representation |
---|---|
bin | 101110000110… |
… | …100001010111 |
3 | 211201222222000 |
4 | 232012201113 |
5 | 11043212320 |
6 | 1111010343 |
7 | 204503133 |
oct | 56064127 |
9 | 24658860 |
10 | 12085335 |
11 | 6904989 |
12 | 40699b3 |
13 | 2671ab2 |
14 | 18683c3 |
15 | 10dac90 |
hex | b86857 |
12085335 has 16 divisors (see below), whose sum is σ = 21485280. Its totient is φ = 6445440.
The previous prime is 12085331. The next prime is 12085343. The reversal of 12085335 is 53358021.
12085335 is a `hidden beast` number, since 120 + 8 + 533 + 5 = 666.
12085335 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12085335 - 22 = 12085331 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 12085299 and 12085308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12085331) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 44626 + ... + 44895.
It is an arithmetic number, because the mean of its divisors is an integer number (1342830).
Almost surely, 212085335 is an apocalyptic number.
12085335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12085335 is a deficient number, since it is larger than the sum of its proper divisors (9399945).
12085335 is an equidigital number, since it uses as much as digits as its factorization.
12085335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 89535 (or 89529 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 27.
The square root of 12085335 is about 3476.3968415588. The cubic root of 12085335 is about 229.4842571114.
The spelling of 12085335 in words is "twelve million, eighty-five thousand, three hundred thirty-five".
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