1200113407 has 2 divisors, whose sum is σ = 1200113408. Its totient is φ = 1200113406.

The previous prime is 1200113399. The next prime is 1200113423. The reversal of 1200113407 is 7043110021.

It is a weak prime.

It is an emirp because it is prime and its reverse (7043110021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1200113407 - 2³ = 1200113399 is a prime.

It is a super-2 number, since 2×1200113407² = 2880544379322295298, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1200113507) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600056703 + 600056704.

It is an arithmetic number, because the mean of its divisors is an integer number (600056704).

Almost surely, 2^1200113407 is an apocalyptic number.

1200113407 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200113407 is an equidigital number, since it uses as much as digits as its factorization.

1200113407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 168, while the sum is 19.

The square root of 1200113407 is about 34642.6530017549. The cubic root of 1200113407 is about 1062.6920439393.

Adding to 1200113407 its reverse (7043110021), we get a palindrome (8243223428).

The spelling of 1200113407 in words is "one billion, two hundred million, one hundred thirteen thousand, four hundred seven".