11320033 has 4 divisors (see below), whose sum is σ = 11328768. Its totient is φ = 11311300.

The previous prime is 11320031. The next prime is 11320061. The reversal of 11320033 is 33002311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11320033 - 2¹ = 11320031 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11319995 and 11320022.

It is not an unprimeable number, because it can be changed into a prime (11320031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1993 + ... + 5158.

It is an arithmetic number, because the mean of its divisors is an integer number (2832192).

Almost surely, 2^11320033 is an apocalyptic number.

It is an amenable number.

11320033 is a deficient number, since it is larger than the sum of its proper divisors (8735).

11320033 is an equidigital number, since it uses as much as digits as its factorization.

11320033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8734.

The product of its (nonzero) digits is 54, while the sum is 13.

The square root of 11320033 is about 3364.5256723645. The cubic root of 11320033 is about 224.5342332011.

Adding to 11320033 its reverse (33002311), we get a palindrome (44322344).

The spelling of 11320033 in words is "eleven million, three hundred twenty thousand, thirty-three".