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113247437 is a prime number
BaseRepresentation
bin1101100000000…
…00010011001101
321220002120021112
412300000103031
5212442404222
615123141405
72543405312
oct660002315
9256076245
10113247437
1158a1a526
1231b14865
131a601524
141107cd09
159e1ebe2
hex6c004cd

113247437 has 2 divisors, whose sum is σ = 113247438. Its totient is φ = 113247436.

The previous prime is 113247401. The next prime is 113247443. The reversal of 113247437 is 734742311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109223401 + 4024036 = 10451^2 + 2006^2 .

It is a cyclic number.

It is not a de Polignac number, because 113247437 - 28 = 113247181 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113247457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56623718 + 56623719.

It is an arithmetic number, because the mean of its divisors is an integer number (56623719).

Almost surely, 2113247437 is an apocalyptic number.

It is an amenable number.

113247437 is a deficient number, since it is larger than the sum of its proper divisors (1).

113247437 is an equidigital number, since it uses as much as digits as its factorization.

113247437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 14112, while the sum is 32.

The square root of 113247437 is about 10641.7779059704. Note that the first 3 decimals coincide. The cubic root of 113247437 is about 483.8114333285.

Adding to 113247437 its reverse (734742311), we get a palindrome (847989748).

The spelling of 113247437 in words is "one hundred thirteen million, two hundred forty-seven thousand, four hundred thirty-seven".