Base | Representation |
---|---|
bin | 100001101110000… |
… | …0100010100100000 |
3 | 2220211222122211021 |
4 | 1003130010110200 |
5 | 4304121244300 |
6 | 304134255224 |
7 | 40016002144 |
oct | 10334042440 |
9 | 2824878737 |
10 | 1131431200 |
11 | 530733009 |
12 | 276ab7514 |
13 | 150537223 |
14 | aa3a1224 |
15 | 694e3d1a |
hex | 43704520 |
1131431200 has 72 divisors (see below), whose sum is σ = 2809038960. Its totient is φ = 444883200.
The previous prime is 1131431173. The next prime is 1131431269. The reversal of 1131431200 is 21341311.
It is a super-3 number, since 3×11314312003 (a number of 28 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 35215 + ... + 59185.
It is an arithmetic number, because the mean of its divisors is an integer number (39014430).
Almost surely, 21131431200 is an apocalyptic number.
1131431200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1131431200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1404519480).
1131431200 is an abundant number, since it is smaller than the sum of its proper divisors (1677607760).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1131431200 is a wasteful number, since it uses less digits than its factorization.
1131431200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24050 (or 24037 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 16.
The square root of 1131431200 is about 33636.7537078119. The cubic root of 1131431200 is about 1042.0199892275.
Adding to 1131431200 its reverse (21341311), we get a palindrome (1152772511).
The spelling of 1131431200 in words is "one billion, one hundred thirty-one million, four hundred thirty-one thousand, two hundred".
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