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1100122013 is a prime number
BaseRepresentation
bin100000110010010…
…1000011110011101
32211200001222200202
41001210220132131
54223112401023
6301055233245
736155611544
oct10144503635
92750058622
101100122013
11514a98a51
12268518825
13146bc4393
14a617115b
15668ac128
hex4192879d

1100122013 has 2 divisors, whose sum is σ = 1100122014. Its totient is φ = 1100122012.

The previous prime is 1100121973. The next prime is 1100122057. The reversal of 1100122013 is 3102210011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 567297124 + 532824889 = 23818^2 + 23083^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1100122013 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100121985 and 1100122003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100122063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550061006 + 550061007.

It is an arithmetic number, because the mean of its divisors is an integer number (550061007).

Almost surely, 21100122013 is an apocalyptic number.

It is an amenable number.

1100122013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100122013 is an equidigital number, since it uses as much as digits as its factorization.

1100122013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 1100122013 is about 33168.0872677337. The cubic root of 1100122013 is about 1032.3182811949.

Adding to 1100122013 its reverse (3102210011), we get a palindrome (4202332024).

The spelling of 1100122013 in words is "one billion, one hundred million, one hundred twenty-two thousand, thirteen".